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22s-11s^2=0
a = -11; b = 22; c = 0;
Δ = b2-4ac
Δ = 222-4·(-11)·0
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-22}{2*-11}=\frac{-44}{-22} =+2 $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+22}{2*-11}=\frac{0}{-22} =0 $
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